To find whether an entered number is armstrong or not

In this programme I have given the concept that whether the input number is armstrong or not.
For this we have to be clear about what the armstrong number is:
I will make clear about it by the help of example:

For example: 153 is armstrong  number because 1^3*5^3*3^3 is 153 itself. So if the summation of the entered number is the number itself then it is called armstrong number.
The main source code of this programme is given below:

	#include<stdio.h>
	#include<conio.h>
	int main()
	{
	int r,n, num,c,sum;
	printf("enter any number");
	n=num;
	sum=0;
	while(n>0)
	{
	r=n%10;
	c=r*r*r;
	sum=sum+c;
	n=n/10;
	}
	if(num==sum)
	{
	printf("the no is armstrong");}
	else
	{
	printf("the no is not armstrong");
	}
	getch();
	}

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